Question

c++ show code thanks,

only use library <iostream>

Question 1 Write the following two functions The first function accepts as input a two-dimensional array of integers. It returns two results: the sum of the elements of the array and the average The second function accepts as input a two-dimensional array of integers and integer value V. It returns true if the value V is found in the array, false otherwise. Write a main program that declares and initializes the following array: int box08,0,-4, 74,5,13,42), (29-7,45,4, 100,23.-3,613 Your program needs to call both functions and display appropriate messages

Answer 1

#include<iostream>
#include<algorithm>
using namespace std;
#define N 4 //defind dymention of array
#define M 4
float sumAndAvg(int ar[][N]){
  
int s=0; //for sum of element
float c1=0; //maintain count of array
for(int i=0;i<M;i++){
for(int j=0;j<N;j++){
s+=ar[i][j]; //keep summing array element
c1++; //increase the count
}
}
cout<<"sum of numbers: "<<s<<endl; //one function can only return one value
//so print sum here return avg
float avg=s/c1; //avg= sum/no of elements
return avg; //return avg
}
//return true if element found else false
bool find(int ar[][N],int v){
for(int i=0;i<M;i++){
for(int j=0;j<N;j++){
if(ar[i][j]==v) //if element is v return true
return true;
}
}
return false; //else false
}
// Driver program to test above methods
int main()
{
int box[][N] = {{11, 8,0,-4}, //defind given 2D array
{74, 5,13,42},
{29,-7,45,4},
{100,23,-3,6}
};
cout <<"avg of numbers: "<<sumAndAvg(box)<<endl; //call sumAndAvg function
int v=3;
bool isAvailable=find(box,v); //call find function
if(isAvailable)
cout<<v<<" Found ";
else
cout<<v<<" Not Found";
return 0;
}

output

sum of numbers: 346
avg of numbers: 21.625
3 Not Found