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A particle of mass 3.2 kg moves under the influence of the force F(x) = (−5x^2...

A particle of mass 3.2 kg moves under the influence of the force F(x) = (−5x^2 + 7x) N. If its speed at x = −2.8 m is v = 29.0 m/s, what is its speed (in m/s) at x = 2.8 m?

____m/s

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Answer #1

work done by F = change in Kinetic energy We uf = - ser fx dx - 5x2+7x I, da WE = -73•17 Imve - v = -73.17 = - 2x73-17 m = -2

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