How long will it take to recover an investment of $5,000 at 3% interest rate under the following independent scenarios?
a. $800 anually
b. $100 monthly
c. An increasing gradient of $400 per year
a. For first scenario, we obtain the following excel:
| Time (in years) | Interest rate factor | Loan amount | Loan + Interest | Amount paid | Remaining loan amount |
| 0 | 1 | 5000 | 5000 | 5000 | |
| 1 | 1.03 | 5000 | 5150 | 800 | 4350 |
| 2 | 1.03 | 4350 | 4480.5 | 800 | 3680.5 |
| 3 | 1.03 | 3680.5 | 3790.915 | 800 | 2990.915 |
| 4 | 1.03 | 2990.915 | 3080.642 | 800 | 2280.64245 |
| 5 | 1.03 | 2280.642 | 2349.062 | 800 | 1549.061724 |
| 6 | 1.03 | 1549.062 | 1595.534 | 800 | 795.5335752 |
| 7 | 1.03 | 795.5336 | 819.3996 | 800 | 19.39958246 |
| 8 | 1.03 | 19.39958 | 19.98157 | 800 | -780.01843 |
Clearly, the investment is recovered in 8 years
b. For second scenario, we have the following excel:
| Time (in months) | Interest rate factor | Loan amount | Loan + Interest | Amount paid | Remaining loan amount |
| 0 | 1 | 5000 | 5000 | 5000 | |
| 1 | 1.0025 | 5000 | 5012.5 | 100 | 4912.5 |
| 2 | 1.0025 | 4912.5 | 4924.781 | 100 | 4824.781 |
| 3 | 1.0025 | 4824.781 | 4836.843 | 100 | 4736.843 |
| 4 | 1.0025 | 4736.843 | 4748.685 | 100 | 4648.685 |
| 5 | 1.0025 | 4648.685 | 4660.307 | 100 | 4560.307 |
| 6 | 1.0025 | 4560.307 | 4571.708 | 100 | 4471.708 |
| 7 | 1.0025 | 4471.708 | 4482.887 | 100 | 4382.887 |
| 8 | 1.0025 | 4382.887 | 4393.844 | 100 | 4293.844 |
| 9 | 1.0025 | 4293.844 | 4304.579 | 100 | 4204.579 |
| 10 | 1.0025 | 4204.579 | 4215.09 | 100 | 4115.09 |
| 11 | 1.0025 | 4115.09 | 4125.378 | 100 | 4025.378 |
| 12 | 1.0025 | 4025.378 | 4035.442 | 100 | 3935.442 |
| 13 | 1.0025 | 3935.442 | 3945.28 | 100 | 3845.28 |
| 14 | 1.0025 | 3845.28 | 3854.893 | 100 | 3754.893 |
| 15 | 1.0025 | 3754.893 | 3764.281 | 100 | 3664.281 |
| 16 | 1.0025 | 3664.281 | 3673.441 | 100 | 3573.441 |
| 17 | 1.0025 | 3573.441 | 3582.375 | 100 | 3482.375 |
| 18 | 1.0025 | 3482.375 | 3491.081 | 100 | 3391.081 |
| 19 | 1.0025 | 3391.081 | 3399.558 | 100 | 3299.558 |
| 20 | 1.0025 | 3299.558 | 3307.807 | 100 | 3207.807 |
| 21 | 1.0025 | 3207.807 | 3215.827 | 100 | 3115.827 |
| 22 | 1.0025 | 3115.827 | 3123.616 | 100 | 3023.616 |
| 23 | 1.0025 | 3023.616 | 3031.176 | 100 | 2931.176 |
| 24 | 1.0025 | 2931.176 | 2938.503 | 100 | 2838.503 |
| 25 | 1.0025 | 2838.503 | 2845.6 | 100 | 2745.6 |
| 26 | 1.0025 | 2745.6 | 2752.464 | 100 | 2652.464 |
| 27 | 1.0025 | 2652.464 | 2659.095 | 100 | 2559.095 |
| 28 | 1.0025 | 2559.095 | 2565.493 | 100 | 2465.493 |
| 29 | 1.0025 | 2465.493 | 2471.656 | 100 | 2371.656 |
| 30 | 1.0025 | 2371.656 | 2377.585 | 100 | 2277.585 |
| 31 | 1.0025 | 2277.585 | 2283.279 | 100 | 2183.279 |
| 32 | 1.0025 | 2183.279 | 2188.738 | 100 | 2088.738 |
| 33 | 1.0025 | 2088.738 | 2093.959 | 100 | 1993.959 |
| 34 | 1.0025 | 1993.959 | 1998.944 | 100 | 1898.944 |
| 35 | 1.0025 | 1898.944 | 1903.692 | 100 | 1803.692 |
| 36 | 1.0025 | 1803.692 | 1808.201 | 100 | 1708.201 |
| 37 | 1.0025 | 1708.201 | 1712.471 | 100 | 1612.471 |
| 38 | 1.0025 | 1612.471 | 1616.503 | 100 | 1516.503 |
| 39 | 1.0025 | 1516.503 | 1520.294 | 100 | 1420.294 |
| 40 | 1.0025 | 1420.294 | 1423.845 | 100 | 1323.845 |
| 41 | 1.0025 | 1323.845 | 1327.154 | 100 | 1227.154 |
| 42 | 1.0025 | 1227.154 | 1230.222 | 100 | 1130.222 |
| 43 | 1.0025 | 1130.222 | 1133.048 | 100 | 1033.048 |
| 44 | 1.0025 | 1033.048 | 1035.63 | 100 | 935.6303 |
| 45 | 1.0025 | 935.6303 | 937.9694 | 100 | 837.9694 |
| 46 | 1.0025 | 837.9694 | 840.0643 | 100 | 740.0643 |
| 47 | 1.0025 | 740.0643 | 741.9145 | 100 | 641.9145 |
| 48 | 1.0025 | 641.9145 | 643.5193 | 100 | 543.5193 |
| 49 | 1.0025 | 543.5193 | 544.8781 | 100 | 444.8781 |
| 50 | 1.0025 | 444.8781 | 445.9903 | 100 | 345.9903 |
| 51 | 1.0025 | 345.9903 | 346.8552 | 100 | 246.8552 |
| 52 | 1.0025 | 246.8552 | 247.4724 | 100 | 147.4724 |
| 53 | 1.0025 | 147.4724 | 147.8411 | 100 | 47.84105 |
| 54 | 1.0025 | 47.84105 | 47.96065 | 100 | -52.0393 |
Hence, investment is recovered in 54 months.
c. For this scenario, we have the following excel:
| Time (in years) | Interest rate factor | Loan amount | Loan + Interest | Amount paid | Remaining loan amount |
| 0 | 1 | 5000 | 5000 | 5000 | |
| 1 | 1.03 | 5000 | 5150 | 400 | 4750 |
| 2 | 1.03 | 4750 | 4892.5 | 800 | 4092.5 |
| 3 | 1.03 | 4092.5 | 4215.275 | 1200 | 3015.275 |
| 4 | 1.03 | 3015.275 | 3105.733 | 1600 | 1505.73325 |
| 5 | 1.03 | 1505.733 | 1550.905 | 2000 | -449.094752 |
Here, investment is recovered in 5 years.
How long will it take to recover an investment of $5,000 at 3% interest rate under...
How long will it take to recover an investment of $10,000 at 10% interest rate under the following scenarios? a. $2,400 annually b. An increasing gradient of $1,125 per year c. $200 monthly d. Why are the answers to parts a, b, and c equal or different? Show cash flow diagrams and necessary equivalent models.
How long will it take $5,000 investment to grow to $6,500 at an annual rate of 7% compounded semi-annually
44. 31. How long will it take $5000 to grow to $6500 if the investment earns interest at the rate of 6%/year com- pounded monthly? 32. How long will it take $12,000 to grow to $15,000 if the 45 investment earns interest at the rate of 4%/year com- pounded monthly? 33. How long will it take an investment of $2000 to double if 46 the investment earns interest at the rate of 5%/year com- pounded monthly? We were unable to...
an $ 100 How long will it take to double in value if for investment of the interest rate is compour undled continously, 8.5% per year, a) 0.085 In (2) b) In 120o) 0.085 C.) In 127 (Please choose the letter 0.085 of the correct answer) d.) In (2) 8.5
3-6 How long will it take for an investment to double at a 6% per year . (a) simple interest rate (b) compound interest rate Contributed by Hamed Kashani, Saeid Sadri, and Baabak Ashuri, Georgia Institute of Technology
(a) How long will it take an investment to double in value of the Interest rate is 6% compounded continuously? (Round your answer to one decimal place.) 11.6 years (b) What if the interest is compounded annually? (Round your answer to one decimal place.) x years
1. How long will it take for an investment of $1,500 to accumulate to $3,000 if you earn 10% per year? (express answer in years to 2 decimal places) __________ 2. What is $5,000 to be received in 3 years worth today if the interest rate is 12% per year compounded quarterly? A. $3,559 B. $7,025 C. $3,507 D. $7,129 3. What is the FV in 9 years of $4,000 invested today when the annual percentage rate is 12% compounded...
How long will it take for a lump-sum investment to triple in value at an interest rate of 1.5% per six-months, compounded continuously? For the lump sum investment to triple in value at an interest rate of 1.5% per sx months compounded continuously, twill take time periods
a) How long does it take to recover the investment?
How many years is the payback period
Camptown Togs, Inc., a children's clothing manufacturer, has always found payroll processing to be costly because it must be done by a clerk. The number of piece-goods coupons received by each employee is collected and the types of tasks performed by each employee are calculated. Not long ago, an industrial engineer designed a system that partially automates the process by means of a...
8.6.50 How long will it take for an investment to triple, if interest is compounded continuously at 7%? It will take years before the investment triples. (Round to the nearest tenth of a year.)