Question

At what separation is the electrostatic force between a +10.7 μC point charge and a +28.2 μC point charge equal in magnitude to 1.88 N ?

Answer 1

Given data:

chage q1 = +10.7 μC

charge q2 = +28.2 μC

electrostatic force = 1.88 N

we know that formula for electrostatic force as

F = kq₁q₂$\div$(r²)

r^{2 =} kq₁q₂$\div$(F)

r² = 9$\times$10⁹$\times$10.7$\times$10^-6$\times$28.2$\times$10^-6$\div$(1.88)

r = 1.20187 m   

please ask me if u have any doubts regarding this