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2. The composite body shown below is composed of two different materials, (1) and (2) (a) What are the boundary and interface

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Answer #1

Boundary and interface conditions

The traction continuity based on discontinuity of material in y directions.

Based on cauchy stress tensor, ny = 1, nx = nz = 0;

T_x = \sigma_{xx}n_x+ \sigma_{xy}n_y+ \sigma_{xz}n_z.....................Eq(1)

T_y = \sigma_{xy}n_x+ \sigma_{yy}n_y+ \sigma_{yz}n_z.......................Eq(2)

T_z = \sigma_{xz}n_x+ \sigma_{yz}n_y+ \sigma_{zz}n_z........................Eq(3)

From equations (1), (2) and (3)

T_x = \sigma_{xy}, T_y = \sigma_{yy}, T_z = \sigma_{xz},.....................Eq(4)

Therefor the stress components \sigma_{xy}, \sigma_{yy}, \sigma_{xz} are uniform

i.e., 2 ................................Eq(5)

ol1 σ(2)...................................Eq.(6)

where, superscript c, (1) and (2) denotes the composite, materials (1) and (2) respectively.

As the bonding is perfect and material is continuous in x - direction.

Therefore, the strain component

2...........................Eq(7)

The volume average stress/strain component i.e non-uniform component are

\sigma_{xx}^c = V_{1}\sigma_{xx}^{(1)}+V_2 \sigma_{xx}^{(2)}.......................Eq(8)

\varepsilon _{yy}^c =V_1\varepsilon_{yy}^{(1)}+V_2 \varepsilon_{yy}^{(2)}.........................Eq(9)

View + -$ ry........................Eq(10)

(b) If there is a slip interface condition then Equation (1) - (3) will not be valid .

Uniform strain components

2.........................Eq.(7)

The non uniform components in x direction

\sigma_{xx}^c = V_{1}\sigma_{xx}^{(1)}+V_2 \sigma_{xx}^{(2)}............Eq.(8)

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