Question

Calculate voltage and current across R_L using mesh or nodal analysis. Verify using Thevenin’s and Norton’s Theorems. (RL = 1.5k)

3. 13 3.3ke3 Prelab 5 Task li Calculate voltage across R and current using mesh or nodal analysis. Verify using Thevenins & Norton's Theorems. 15V 3. 30

Answer 1

In Mesh - . KULegn 5 + 2.78 103 (I, Ig) +3.3 x 103 (I – I3)=0 6 I, - d. 7 Ig -3.3 Iz = 15* 4.5V R 1 Re 4 -13)=0 ISUT O H 2 -3.3 Iz = 15+103 skule ome Zuz 2 In Mesh 0.4 . 3.3% 1031 I + RL (ID - Ig) + 4.5+ 9.7x103 (Ig - I) = 0 Vaba Iz Ig) RL R = 1.5k 1} 3- 3 x 103 g + 15x103 (13-1x) + 4-5 + 2-4X10% (12-1)=0 7.5*10* I, + 9.4x 1031, -1.510*19 =-4-5 9-4-1, -7.512 + 1-5.13 = 4.5*103-@ In Mesh 8.3x103 (13-1,)-4.5 +1.5*10% 13 -19) + -4x pongo -3. 3x103 I, - 1.5*103 I2 + 6X103 Iz = 4.5 - 3.31, -1-5.19 + 6 I3 = 4-5 x103 - From En (3) I = 6.47 mA I = 2.72 mA, I = 4.99 mA current through R = Ig Is = 2.27 mA Voltage across R > Vab = LIB I) Vab = 9.94x10-3x 1.5 x 103 - 8.405

Trika $ 3.3KA using The venin's Theoremy for equivalent Resistance Rth (Thevenin's Resistance) voltage source & shortckt - 66 150 $ 459 9.kh 3.3 KA K Tazky 88.3k4 3.5kn 9.1 K Rth сть $3.5kr 7 a 82.74 79 arth 9.7 k i and 3.3kd are. in parallel and parallel combination of both are in series. R, = d.7k111 3.3k1 R2 = 3.8kallatky R = d.7 x 103 x 3.5x100 (3.3+27X10 (9.443.3) x103 R2=1.485k 1 R = 9.485k1 Ro-3.3x2.7 x 103 103 V a Rth Rth = R + R2 Rth = 2.97k1 For Uth Calculation & In mesh → KULA 15+ DJ x103 (I-Ig) 32.7k1 334 4-5 V 9A Ⓡ 6 x70 3.1 - 6x1031, 15 6 LE In mesh & -+8.319-1 +3.8)x10-219.7+3.3) X103-01 - 61, *103 +19x1031=0 -

From EQ n f . 61 – 6 Ig = 15x10 3 -644 +12 19 = 0 I GI2 = 15x103 Is = d.5mA Ij = 5 MA Now for Uth in mesh 6 → 8.3 x 103 I – 3.3x1031 – 4.5+ Uth & 2.72 10 8 12 0 3.34123x8.5x103-3-3x108x58103-4-5 +9.4*103x2.5x102 of Uth = 0 With = 4.5+ 16.5 - 8.25 -6.75 Uth = 60 Now Thevenin's circuit - eu ] Uth Rony R I = Rth the uth I I = 6 + 1.53X103 = 4:47 Il = 1.34 mA 6x10 (2.9 UthRL -- IRL = 1.34*10* 1.5x103 Rthth V = d.olv