Question

eriod Name Date HW 11:2 Electrostatic Potential 3. Two parallel plates are arranged as shown to the right. The. E electric field between the plates is uniform and is directed from the positive plate to the negative plate as shown. The electric l← e field strength is E - 60,000 N/C and the two plates are d 6.00 cm apart. A particle which has a charge of q =-0.01 50μC is initially placed at point A. a. How much work would have to be done to move this particle1.00cm B from point A to point B? 6.00cm b. What is the potential difference between point A and point B? c. How much work would have to be done in moving this particle from point A to point C? d. What is the potential difference between points B and C? Suppose that another particle, which has a charge of 2.00 μC, is placed, initially, on the negative plate. This particle is then moved from the negative plate to the positive plate. e. How much work would be done in moving this particle from the negative plate to the positive plate? f. What will be the potential difference between these two plates? 149 Honors Physics by James J. Kovalcin 2004, published by TEACHING point as part of the Expert Systems for TeachersT Series

Answer 1

Work done = force middot displacement . (F vector middot d vector) = q f d angle between F vector and d vector = + 0.0150 times 10^-6 times 60000 times 4 times 10^-2 F vector = + 3600 times 10^-8 w = + 0.36 times 10^-4 Joules potential difference = Fd = 6000 times 4 times 10^-2 = 2,40,000 times 10^-2 = 2400 V \r\n w = F vector middot d vector Tan(t0 = 5/4 theta = Tan^-1(5/4) theta = 21.34019175 w = q F d Cos theta = 0.015 times 10^-6 times 60000 times 6.403124237 times 10^-2 times 0.0624695047 = 0.015 times 60000 times 6.403124 times 0.624695047 times 10^-8 = 0.3599 times 10^4 Joules potential difference = w/q = 239999.9909 times 10^-2 = 2399.999 V Kindly ask rest of the questions as separate questions.