Question

。 20 hat agleis he E- feld going angle in Keaion

Answer 1

For medium 1 and 2 E_1t = E_1 cos 70 degree E_1n = E_1 sin 70 degree Applying boundary condition of filed across the boundary between Medium 1 & medium 2) 2) D_in = D_2 n rightarrow Assuming charge free boundary Rightarrow E_21 = E_1t = E_1 cos 70 degree (1) 0_1n = E_1 E_in = 5 E_0 E_1 sin 70 degree D_2n Rightarrow E_2n = D_2 n/E_2 = 5 E_0 E_1 sin 70 degree/2 Elementof = 2.5 E_1 sin 70 degree \r\n For medium 2) and 3) = 2.5 E_1 sin 70 degree/E_1 cos 70 degree = 2.5 tan 70 degree Rightarrow theta 81.72 degree theta_1 = theta - 70 degree Rightarrow theta_1 11.72 Applying boundary condition E_2 t = E_2 cos theta_1 = E_3 t E_2n = E_2 sin theta_1 Rightarrow D_2 n = E_n E_2 n = 2 Eo E_2 n = 2 Eo E_2 sin theta_1 D_2 n = D_3 n = 2 E_0 E_2 sin theta_1 Rightarrow E_3 n = D_3 n/E_3 = 2E_0 E_2 sin theta_1/5E_0 = 0.4 E_2 sin theta_1 Rightarrow tan alpha = E_3 n/E_3 t = 0.4 E_2 sin theta_1/E_2 cos theta_1 = 0.4 tan theta_1