Question

Draw the BMD and SFD for the following problems. 6 KN 6 KN 12 kN.m 12 kN.m LB 2 m 2m-2m- W = 8kN W = 8kN L = 3mL = 3m = 3m L = 6m 500 lb 200 lb 300 lb B 8f- 8f- +

Answer 1

6K . TA 0 Moment about A: +(6x2) -(RBXL) +(6xb) = 0 -12-4 RB +36=0 +4R8= +24 RB = 6 kN] - 6+RA + RB-6=0 - 12+6+RA=0 . [RA = 6kN] Bending Moment calculation : Mozo Mg = -6x2) = -12kw m MA: -(646) +(6x4) +(6x) = -34+24 = -12 km M E -(648) + 6(6) + 6(2) = -48 +36+12 = 0

8kN 6N - X Sheen force: SfA=-8kN State 8-8=-16 KN 2 A -8 Ste to RW By calculation : MB = 48 x 3) = -24 KN 2 2 2) (Padat 2 Mc = +8+6) + (-8x3)=(-48) - 24 = -12 kN past? 2,6733172054 205 2.

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moment about B: (RCA) -(500x8) at (300x8) 20 16 Rc-4000 + 2400 20 Re = 1000 16 The=10016) Efyco Rc-500-200 + RB-300 co s 100-1000 +RBO 1 RB =900lb) shear force Sfo = -3oolb SFB = -300+70o = hoolb SFA = 400-500 = -100lbom SFC -100+100 = 0 lb Bending moment MD = 0 MB = (-300x8) =~2400 lb MA = 6-300x16) +(400*8) =4880+3200 3-1600 lb M = (-300x 24) +400x16) - 500x8)=-7200+ 6400-4000 - = - 4800 lb