Answer:-
Decision is Reject Ho
because
true mean (16) is not falls in the range confidence interval , therefore we reject the null hypothesis
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QUESTION 5 You have created a 90% confidence interval for u with the result 10 SUS...
We have created a 95% confidence interval for µ with the result (10, 16). What conclusion will we make if we test H0: µ = 16 versus HA: µ ≠ 16 at α = 0.05? Reject the null hypothesis. Accept the null hypothesis. Fail to reject the null hypothesis. Reject the alternative hypothesis. No decision can be made from the information given.
We have created a 95% confidence interval for µ with the result [10, 15]. What conclusion will we make if we test the claim µ = 15.2 with a 97% confidence? a. Accept the claim that µ = 15.2 with a 95% confidence. b. Accept the claim that µ = 15.2. c. Do not accept the claim that µ = 15.2. d. No decision can made from the information given.
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Question 6 1 pts Solve the problem. We have created a 99% confidence interval for with the result (8,13). What conclusion will we make if we test at a= = .012 Fail to reject Ho Reject Ho and support Ha. Accept Ho rather than Ha. O Conclude the mean is not between 8 and 13. We cannot tell what our decision will be with the information given. Question 5 1 pts The variance for X...
The following joint probability dessity function is given belo etermine the following 1) Marginal peobability distribution fuction ef x 34 2) Conditional probability distribution of X giveny-1aod A) 0.5 B)03x/y D) 0.5 xy 3) sample standard deviation is C6.782 B) 6.305 D) 5.639 A) 6.066 4) we have created a 90% confidence interval fix μ with be result (1 l, 16). what conclusion will we make ifwetest 16-18v,庵"18ata».10? A) Reject Ho in favor ofHa B) Fail to reject Ho C)Accept...
5) Let's examine the relationship between CI's and hypothesis tests: (a) You calculate a 90% confidence interval for p and come up with (-10, 26). If you test Hay=-12 and use a = .10, will you reject H.? Why or why not? (b) Now you calculate a 95% CI for and come up with (-3,7). If you test Hiu= 8 and use a = .10, will you reject H.? Why or why not? (c) Finally, you calculate a 95% CI...
5. You have just detemined a 95% 2-sided confidence interval on the difference between the two population means, -H2, where is the population mean yield of chemical process 1 and is the population mean yield of chemical process 2. Your result is L = -1.02 and U 2.32. In a 2-sided test of hypothesis on the equality of these two means, He , what would have been your conclusion? Enter the letter of the correct answer on the answer sheet...
Say a 95% confidence interval for P2 - P2, the difference between two proportions, is (0.152, 0.392). This indicates that the difference between the two proportions is not significant. A) True-- Yes OB) False--No O C) Can't tell without the data Question 7 (1 point) According to National Eye Institute (NEI), in 2010, 61% of Americans with cataract were women and 39% were men. Suppose you want to conduct a test for the difference in proportions to test whether females...
10. Match each description to the correct confidence interval in the diagram below. Must get all matches correct. No partial credit. Fail to reject H. P> 0.05. Not statistically significant despite large sample size, which justifies acceptance of the null hypothesis (Cl captures 1 because the RR estimate is close to 1). Fall to reject H. P> 0.05. Although the RR estimate is close to 1, we cannot accept the null hypothesis since the Ci is wide (imprecise). Cannot distinguish...
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Question 30 1 pts Solve the problem. To help consumers assess the risks they are taking, the Food and Drug Administration (FDA) publishes the amount of nicotine found in all commercial brands of cigarettes. A new cigarette has recently been marketed. The FDA tests on this cigarette yielded mean nicotine content of 24.4 milligrams and standard deviation of 2.2 milligrams for a sample of r9 cigarettes. Construct a 95% confidence interval for the mean nicotine content...
You read in a U.S Census Bureau report that a 90% confidence interval for the median income in 2012 of American households was $51,017 (+ or -) $343. Based on this interval, can you reject the null hypothesis that the median income in this group is $50,000 using test statistics? What is the alternative hypothesis of the test? What is its significance level?