Question

Part II: Determination of the Activation Energy, E. 9. Set up your experiments and make measurements to determine the value of the activation energy, E., of the reaction. In Table 4 list the experimental conditions and data your team measured. In Table 5 list the results calculated from these data and the value of the activation energy you determined for each mixture. Fill in the appropriate headings for each column and indicate all units. Leave any unused cells blank. سام 0 . 0) امام ها سامهم Table 4: Data Measured for Determining the Activation Energy Reaction NAS203 ke kBros Het Mixture 0.0010M 0.010M 0.040M 0.10M Tempc time's Drops 10.0 260 10.0 ML 10.0 ML (0.0 ML 100ML 3 24. 112 10.0ML (0.1 AL DO AL 100 ML 3 32.0 55 4 100nL 100 ML 10.0ML 10.0 ML 40. 34 10.0 ML DOML 100ML 10.0 M6 3 56.0 14 No penalty for using these data, 5pt. Bonus for using your own). Table 5: Results used for Determining the Activation Energy Reaction Mixture Average Activation Energy: Units: 10. Attach one or more additional pages detailing how you used the data and results in Tables 4 and 5 to determine the activation energy above. Include a brief explanation of your method. Include sample calculations, graphs, or other supporting work. A Chemical Clock - Your Report Page 4

Answer 1

We know that for activation energy Co Ks = 5 1 4 - 1 1/2) tate are time f Activation energy boost not depend on volume of solution, it depend on nature. so it will depend on rate worltont Rate constant is innendly propotional to time. Reaction mixture 192 in 260 2E 112 8.314 + 283 -1.) 29711) R = 8.314 kPama Kinalk T = 10 +213=883k Te = 24.1+2+3=297.1k 0.842 700 = EX 1-676 E-417 K7 kmol &=0.5024 kJ) Karol Reachiona mixture 283 In 12 ( 365 0.711 X 8.3142 EX8.718 &= 0.678 kJ/ linol Reaction mixture 3 & 4 has a los aman 0.480988.314 2 EX 8.482 3.998 2 EX8.482 = 0.471 kJ/ Kano)

Reaction mixture 445 was born 0.887 X 8.314 - Ex 9.885 Eu-0.746 Aug activation energy is o.saa ky kond) 0.6 kJ l kmol
wwith the help of activation energy formula we will calculate the activation energy. as we know activation energy only depend on nature of compound not on volume so volume of solution will not be used for calculation. activation energy depend of rate and rate depend on rate constant. rate constant depend on time so time will be used for calculation. which is inversely propotional to rate constant.