Question

8. (12 pts) For the following reaction, identify the oxidation number for each element on each side of the equation; identify what is oxidized and what is reduced; identify the oxidizing agent and the reducing agent; tell how many electrons are transferred as the reaction takes place. 2 MnCO3(s) + O2(g) → 2 MnOz(s) + 2 CO2(g) 9. (4 pts) What molarity of sodium ions results when 1.00 moles of Na2SO4 are combined with enough water to make 2.00 L of solution?

Answer 1

reduced reduced O.N +4,-2 +4 -2 & Given reaction is r 2 Mn CO₂ (s) + O₂(g) 2 MnO2 (s) + 200₂ (9) +2, +4,-2 o I oxidised The substance which gets oxidised acts as reducing agant And the substance which Jets reduced acts as oxidising aghet. i is reduced as o2 ) ₂ acts as oxiclising aghet concor Mucoz (mut2) is oxidised as MnO₂ (Muth) ) mn acts as reducing agent. No. of elections trausffered = Total change in the oxidation State of any element involved in the reaction Ex: zmuth - 2 muty 2 x (+2) - 2x(+4) +4 +8 =) change in o.M=8-4=4 . No.f electrons transferred = 4 9 Given compound: Naz Soy (sodium sulfate) n=1 mole, V=2 Lit Molarity = No. of moles = n = 2 = 0.5 m. Volume chit) flit) but Na, soy - 2 Na+ + sou² Molarity of Sodiamion (Mat) = 2x0.5 = 1M. (since there are two Nations in the formula)