Question

Write out the memory map for the following code, providing all values at the end of execution.
How many total bytes does this code declare for variables?

double testd; struct frog h: int testi; double .xy: struct frog turtle, apple, tv[3] testi-2; apple-kturtle; apple->x-ktestd; *(turtle.x)-7.3; apple).y-3.6 turtle.y-1.5 for (testi-o ; te8tjc3 ; test i++) tv [testi] .x-a(tv [ (test1+1 )%3] . y) ;

Answer 1

IF YOU HAVE ANY DOUBTS COMMENT BELOW I WILL BE THERE TO HELP YOU

ANSWER:

EXPLANATION:

AS PER THE QUESTION GIVEN

double testd;   // 8 bytes

int testi;      // 4 bytes

struct frog

{

double *x,y;   // 4+8 = 12 bytes

}

struct frog turtle,*apple,tv[3];   // 12 bytes , 4 bytes , 12*3 = 36 bytes

testi = 2;

apple = &turtle;

apple->x = &testd;

*(turtle.x) = 7.3;

(*apple).y = 3.6;

turtle.y = 1.5;

for(testi=0;testi<3;testi++)

tv[testi].x = &(tv[(testi+i)%3].y);

*(tv[1].x) = 6.4;

Memory Map

testd (address 3400)

7.3

testi (address 6800)

turtle (address = 2002)

&testd = 3400

1.5

apple

2002

tv[3]

tv[0]:x = 3988

y

tv[1] : x = 4000

2y

tv[2]:4012

0

x

4000

Total bytes used for variables =

double testd;   // 8 bytes

int testi;      // 4 bytes

struct frog turtle,*apple,tv[3];   // 12 bytes , 4 bytes , 12*3 = 36 bytes

= 8+4+12+4+36 = 64 bytes

HOPE IT HELPS YOU

RATE THUMBSUP PLEASE