Question

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The patient recovery time from a particular surgical procedure is normally distributed with a mean of 5.1 days and a standard deviation of 2.1 days. What is the probability of spending more than 4 days in recovery? (Round your answer to four decimal places.) - 13 points My Notes Ask Your Teacher Let X be the random variable representing the number of calls received in an hour by a 911 emergency service. A probability distribution of X is given below. 2 Value of X 0 Probability P(x) 0.32 3 4 0.1 0.06 (a) Suppose the probability that X = 1 and the probability that X = 2 are the same. What are these probabilities? (b) What is the probability that at least one call received in an hour? (c) What is the expected number of 911 calls in an hour? -/1 points My Notes Ask Your Teacher An airline has found about 8% of its passengers request vegetarian meals. On a flight with 160 passengers the airline has 11 vegetarian dinners available. What's the probability that it will be short of vegetarian dinners? (hint: Let X be the number of vegetarians. Identify a probability model for X. Write a probability expression for X that reflects 'Short of vegetarian dinners' and compute.) (Click to use an online probability calculator.) (round to 4 decimal places)

Answer 1

LO. X= pation recovery time x~ Normal (M= 5.1, T = 2.1) To find, PCX >4) = P IZ > 4-5.11c P(Z > -0.524) = 10. 69987 3. Les Plxal) = P(x=y=a a) We know , [ PCX = x) = 1 -) 0.32 + ata +0.1 +0,06 x=0 2 = 0.26 = 0,48 + 20 = 1 => a = -0.48 024 up (x=1) = P (X=2) = 0.26). b) P(x 1) = 1-P (X<1) = 1-p (X=0 = 1-0,32 = 0.68). CW nip (x=n) - (Ox 0,32) + ... +(4x2.06. - 11.32). 3. n: 160 þ= 8% = 0.0f : X~ Binomial (1=160, p=0.08 To find, P(x>11) - Move (169) (0.08? 10.93%6^x U = 0 160 x=12 341 Scanned with CamScanner