Question

must be done in C

You will implement a function that matches one of the prototypes below. int maxArray(int size, int* arr); int maxArray(int size, int arr]); The first parameter is the number of elements in the array. The second parameter is an address to the beginning of an int array. In the body of the function, use a looping structure to identify and return the maximum (largest number) of the array. NOTE: The maximum of the same number, say 3 and 3, is 3. In main, define and initialize an integer array with multiple unique elements. Call the function with this array to verify the function is working correctly If you want a challenge write a function that matches the following prototype. It should work identical to the description above with a slightly different call. NOTE: arr below is a pointer to int array with size elements. int maxArray(int size, int (*arr)[size]);

Answer 1

#include <stdio.h>
int maxArray(int size, int *arr);
int main(){
int size = 10;
int arr[10] = {4, 6, 2, 1, 9, 6, 5, 9, 2, 4};
int max;
max = maxArray(size, arr);
printf("The array contains: ");
for(int i = 0; i < size; i++)
printf("%d ", arr[i]);
printf("\nMaximum: %d\n", max);
return 0;
}
int maxArray(int size, int *arr){
int max = arr[0];
for(int i = 1; i < size; i++)
{
if(arr[i] > max)
max = arr[i];
}
return max;
}

output
---
The array contains: 4 6 2 1 9 6 5 9 2 4
Maximum: 9