Question

(1 point) 1581 The null space of A= [271 0 0 ܟܒ ܗ. 0 0 00 0 ®e.pan{[?l} OH. none of the above

Answer 1

A = $\begin{bmatrix} 5 &8 \\ 2 & 7 \end{bmatrix}$

reducing the matrix to reduced row echelon form

Divide row1 by 5 Add (-2 * rown) to row2 Divide row2 by 19/5 Add (-8/5 * row2) to row1

as both the rows are independent

so, null space of A is

$\begin{bmatrix} 0\\ 0 \end{bmatrix}$

option F