Question

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4. An 80-kg man stands in an elevator. What is his apparent weight when 1) the elevators stationary, IT) the elevator accelerates up at 2 m/s?. III) the elevator accelerates down at 2 m/s IV) the elevator cruises up at constant velocity of 1 m/s. A) Draw a free body diagram of the man labeling the two forces (n and weight) acting on him. B) Write Newton's 2nd law, just including the vertical components. C) Put the forces n and mg into part B). D) Solve the result of part C) for n (the apparent weight). E) Plug in the values of m, g, and a to get n for each case. Il) III) IV)

Answer 1

- solution:- w=mg Ist) Elevator is stationary: - Newton's and law, IF (M) = mal In this case, N=mg N=80x 9.8 N. N = 784N and the elevator accelerates up at 2 m/s2: in this case, N=m(gta) N=80 (9.8+2) IN=guun Trd) the elevator accelerates down at am/s² In this case, N = m (ga) & N=80 x 7.8 N=624N With the elevator cruises up at constant velocity of In this case, velocity is constant which means acceleration = 0 & Nang = 80x9.6 = 784 Answer ils