
nment PRINTER VERSION4 BACK NEXT Chapter 04, Problem 028 The drawing (not to scale) shows one...
e alignment of the sun, earth, and orce FSM that the sun exerts on the moon is per- 5.98 × 1024 kg, 8. The distances shown in the drawing are rawing (not to scale) shows on pendicular to the force FeM that the earth exerts on the m are: mass of sun = 1.99 × 1030 kg, mass of earth = mass of moon = 7.35 × 1022 k SM-1.30 × 10 11 m and rEM-3.85 × 108 m. Determine...
Mass of the Sun is 1.99 × × 1030 kg, mass of the Earth is 5.98 × × 1024 kg, mass of the Moon is 7.35 × × 1022 kg. Orbit radius of the Earth is 1.50 × × 1011 m, orbit radius of the Moon is 3.84 × × 108 m. 1) Determine the magnitude of the net force of gravity acting on the Moon during an eclipse when it is directly between Earth and the Sun. (Express your...
Question 1: 25% Find the total gravitational force on the Earth from the Sun and Moon, using the axes shown in the figure. Show your work, write your answer in unit vector notation, and keep 3 significant figures on each component in your answer. Moon 7.35 x 1022 kg 3.85 x 108m Sun 1.50 x 1011m 1.99 x 1030kg 5.97 x 1024 kg Earth
FEMI (3%) Problem 4: When the Moon is directly overhead at sunset, the force by the Earth on the Moon, FEM, is essentially 90° to the force by the sun on the moon, FsM, as depicted in the image. Let FEM=1.99 x 1020 N, FsM= 4.61 x 1020 N, all other forces on the Moon be negligible, and the mass of the Moon be m= 7.35 x 1022 K 2 kg Moon ESM 50% Part (a) What is the magnitude...
1a.Diane (weight 255 N)is practicing on a tightrope that is 6.00 meters long and sags by 0.120 meters. When she is in the middle of the rope, what is the force on eacheyebolt holding the tightrope?1b. Vector A has a magnitude of 3.0 units and makes an angle of -90.0 degrees with the positive x-axis. Vector B has a magnitude of 4.0 units and makes and angle of-120 degrees with the positive x-axis. What is the direction of the vector...
Need help with one and two.
Problem 2 I did just need it double checked.
The following information will aid you in your calculations: Mass of Earth: 5.97 x 104 kg Mass of Sun: 1.99 x 1030 kg Earth-Sun Distance: 1.496 x 108 km Mass of Moon: 7.35 x 1022 kg Earth-Moon Distance: 3.84 x 105 km 1) Calculate the altitude necessary for a satellite to be in a geostationary (geosynchronous) orbit about the Moon. You may need to look...
3. 1 AU = 149 597 970 700 metres, and the Sun’s mass is 1.98855 x 1030 kg. (a) Calculate the apparent tidal force on the two rocks from question 2 due to the Sun, and (b) use your results from questions 2 and 3 to give a qualitative explanation of the difference between spring tides and neap tides. Note: You will have to be careful about significant figures; take the 1-kg mass as an absolute value. Q2 Results 2....
Pluto -1.4 x 10 1.5 x 10 1.02 X 1 Moon 7.36 x 1022 1.991 x 1030 1.74 x 106 6.96 x 108 Sun -13 POINTS SERCP11 7.5.P.044. A 716-kg satellite is in a circular orbit about Earth at a height above Earth equal to Earth's mean radius. (a) Find the satellite's orbital speed. m /s (b) Find the period of its revolution. (c) Find the gravitational force acting on it. Need Help? Read it -18 POINTS SERCP9 7.P.031.MI.FB. A...
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Useful Planetary Data Mean Radius (m) 243 × 106 6.06 × 10° 6.38 × 10° 3.37 × 106 6.99×107 5.85 × 10' 2.33 × 107 221 × 107 1.14 × 10° 1.74 × 10° 696 × 108 Period (s) 7.60 × 106 1.94 × 107 3.156 × 10, 5.94 × 10' 3.74 × 108 9.35 × 108 2.64 × 109 5.22 × 109 782 × 109 Mean Distance from Sun (m) 579 × 100 1.08...
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the question is worth any points
a) The initial ratio of deuterium (D) to hydrogen (H) in a planet's atmosphere was 175000; however, the present ratio is 1/1500 and the initial and final abundances of D are 5 x 10° atoms per m3 and 9 x 106 atoms per m2, respectively. What fraction of deuterium has been lost, and what fraction of hydrogen has been lost in this...