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27. Consider the reaction. NH,HS(s) NH3(g) + H2S(g) At a certain temperature, Ke-8.5 × 10-3 In a reaction mix- ture at this t
solid form or will some of the existing solid decompose as equilibrium is reached?
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Answer #1

Given that,

[NH3 ] = 0.166 M

and [H2S ] = 0.166 M

Qc = [NH3][H2S] = 0.166 * 0.166 = 0.0276 M .... as activities of Solids is one, so [NH4HS] = 1 and is not included in equation

Now, Kc = 8.5 *10-3 < Qc

Thus, we have more concentration of products than in the equilibrium position. so, reaction will shift backward forming more NH4HS.

Hence, More solid will form as equilibrium is reached.

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