Question

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6. Consider that you are conducting a survey on household sizes of a city, by randomly calling people. From all phone calls, 1/3 of the responses reported a household size of 1, 1/3 a size of 2, and another 1/3 a size of 3. What is the average household size of the city? Solution: Consider the ratio of households with size 1, 2, and 3 to be x, y, z, and x+y+z1 (only these three sizes exist) Then the chance to get a response of size 1 is P(R 1)- For households with two people, either one can answer the phone. There- fore, the chance to get a response of size 2 is 2 PR = 2) = x + 2y + 3z And similarly for size 3 PR = 3) = This leads to x - 0.55, y -0.27, and z - 0.18. Therefore, the mean household size is 0.55 * 1 +0.27* 2 + 0.18*3-1.6:3

Answer 1

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