first to draw ICE table.
then using kp to find x.
then to find equilibrium partial pressure.

A Review Constants !! Consider the following reaction: Br2(g) + Cl2(g) = 2BrCl(9) Kp = 1.11...
Consider the following reaction: Br2(g)+Cl2(g)⇌2BrCl(g) Kp=1.11×10−4 at 150 K. A reaction mixture initially contains a Br2 partial pressure of 760 torr and a Cl2 partial pressure of 740 torr at 150 K. Part A Calculate the equilibrium partial pressure of BrCl.
At 400K, the equilibrium constant for the reaction Br2(g) + Cl2(g) ⇌ 2BrCl(g) is KP = 7.0. A closed vessel at 400K is charged with 1.00 atm of Br2(g), 1.00 atm of Cl2(g), and 2.00 atm of BrCl(g). Use Q to determine which of the statements below is true. A. The equilibrium partial pressure of BrCl(g) will be less than 2.00 atm B. The reaction will go to completion since there are equal amounts of Br2 and Cl2 C. At...
23) At 400 K, the equilibrium constant for the reaction Br2(g) + Cl2 (9) 2BrCl (9) is Kp = 70. A closed vessel at 400 K is charged with 1.00 atm of Br2 (g) 1.00 atm of Cl2 (g), and 2.00 alm of BrCl (g). Use Q to determine which of the statements below is true. A) At equilibrium, the total pressure in the vessel will be less than the initial total pressure. B) The equilibrium partial pressures of Br2....
At 400 K, the equilibrium constant for the reaction Br2 (g) + Cl2 (g) <=> 2BrCl (g) is Kp = 7.0. A closed vessel at 400 K is charged with 1.00 atm of Br2 (g), 1.00 atm of Cl2 (g), and 2.00 atm of BrCl (g). What is the equilibrium pressure of Br2? A. 0.86 atm B. The equilibrium partial pressures of Br2 will be the same as the initial value. C. The equilibrium partial pressure of Br2 will be...
Consider the reaction: 2NO(g)+Br2(g)⇌2NOBr(g) Kp=28.4 at 298 K In a reaction mixture at equilibrium, the partial pressure of NO is 111 torr and that of Br2 is 150 torr a)What is the partial pressure of NOBr in this mixture
Consider the reaction: 2NO(g)+Br2(g)⇌2NOBr(g) Kp=28.4 at 298 K In a reaction mixture at equilibrium, the partial pressure of NO is 101 torr and that of Br2 is 150 torr . What is the partial pressure of NOBr in this mixture? Express your answer using three significant figures.
Consider the equilibrium 4. N2(g) 02(g) Br2(g) 2NOBr (g) Calculate the equilibrium constant Kp for this reaction, give the following information (298.15 K) NO (g) +1/2Br2(g) NOBr(g) Ke 4.5 2 NO (g)N2(g) 02(g) Ke 3.0 x 102 5. For the BrCl decomposition reaction 2BrCl(g) Br2(g Cl2(g) Initially, the vessel is charged at 500 K with BrCl at a partial pressure of 0.500 atm. At equilibrium, the partial pressure of BrC is 0.040 atm. Calculate Kp value at 500K
Consider the...
Consider the reaction: 2NO(g)+Br2(g)⇌2NOBr(g) Kp=28.4 at 298 K. In a reaction mixture at equilibrium, the partial pressure of NO is 108 torr and that of Br2 is 158 torr . What is the partial pressure of NOBr in this mixture?
Consider the following reaction: 2NO(g)+Br2(g)⇌2NOBr(g) ,Kp=28.4, at 298 K In a reaction mixture at equilibrium, the partial pressure of NO is 102 torr and that of Br2 is 134 torr . Part A What is the partial pressure of NOBr in this mixture? Express your answer in torrs to three significant figures.
Consider this equilibrium reaction at 400 K. Br2(g)+Cl2(g)↽−−⇀2BrCl(g) ?c=7.0 If the composition of the reaction mixture at 400 K is [BrCl]=0.00628 M, [ Br 2 ] = 0.00304 M, and [ Cl 2 ] = 0.000557 M, A)what is the reaction quotient, ? Q ? B)How is the reaction quotient related to the equilibrium constant, Kc, for this reaction? a)?=?c b)?<?c c) Q > K c