Question

3. Name each of the following compounds using IUPAC nomenclature, including stereochemistry if applicable. (18 points) Br, I "I н "Br

Answer 1

Longest continioues carbon chain has "8" carbons ,rootword as "oct" .Double bond pesent at second carbon atom , suffix is "ene".Isopropyl group is substitutent at 3 rd carbon atom To give the E nomenclature to the double bond, if same priority numbers are in opposite side then the configuration of alkene is E (E)-3-isopropyloct-2-ene 61 b) 5 Longest continioues carbon chain has "6" carbons ,rootword as "cyclohex" .Double bond pesent at first carbon atom , suffix is "ene".Ethyl group is substitutent at first carbon atom and tert-butyl group is substitutent at third carbon atom. 3-tert-butyl)-1- ethylcyclohex-1-ene 3 4 Longest continioues carbon chain has "4" carbons ,rootword as "cyclobut" .Double bond pesent at fifth carbon atom, .Heptyl group is substitutent at first carbon atom. (Z)-hept-5-en-2- ylcyclobutane T 52 Longest continioues carbon chain has "6" carbons ,rootword as "cyclohex" .Methyl group is substitutent at third carbon atom and tert-butyl group is substitutent at first carbon atom. (1R,3R)-1-tert-butyl)-3- methylcyclohexane e) Br, 4321 Longest continioues carbon chain has "4" carbons ,rootword as "but" Single bonds are pesent , suffix is "ane".Bromine groups are present at 2 nd and 3 rd carbon atom н Br (2R,3S)-2,3- dibromobutane

- 2 (R,Z)-3-chlorohept-4-en-1-yne Longest continioues carbon chain has "7" carbons, root word as "hept". Double bond present at 4 th carbon atom "ene". Triple bond present at 1 st carbon atom "yne".Chlorine group is substitutent at 3 rd carbon atom .Same groups are present at same side of the double bonded carbon atom (Z) at 4 th carbon atom .clock wise orientation of priority groups (excluding last priority group) hence configuration is R