The magnetic force on a particle does NOT depend on
A. Mass
B. Charge
C. Speed
D. Magnetic Field Strength
Generally magnetic force F=q(V×B)
From this formula force depends on the charge, speed of charge and Magnetic field strength only. So it is not depends on mass
The magnetic force on a particle does NOT depend on A. Mass B. Charge C. Speed...
1. A charge particle with mass 0.05 mg and charge 0.0050 C moves through a uniform magnetic field of strength 1.000 T. If the particle moves at a speed of 90 m/s, what is the maximum value of the magnetic force that can act on the particle?
The magnetic force on a charged particle moving at a constant speed in a uniform magnetic field will be halved when the angle between the velocity of the particle and the direction of the magnetic field changes from 25.0° to a. 57.7°. b. 50.0°. c. 12.2°. d. 12.5°.
A particle with charge q = 1.00 10^-5 C and mass m = 1.30 10^-4 kg is moving parallel to the Earth's surface at a speed of 1000 m/s. What minimum strength of magnetic field would be required to balance the gravitational force on the particle?
36) A charged particle of mass m and charge q, is traveling along a magnetic field, B, with speed v. What is the magnitude of the force the particle experiences? a) zero a) zero b) ave b) gvB c mv/lCB
A particle with a charge of 0.33 C is moving at right angles to a magnetic field with a magnitude of 1.27 T. If the particle has a speed of 730 m/s, what is the magnitude of magnetic force acting on the particle?
A charged particle is moving in a uniform magnetic field at a speed of 1.1×103m/s in a direction 73° from the direction of the field. The particle’s charge is 4.7 μC and the magnetic force acting on it is 0.0012 N. What is the strength of the magnetic field?
please do all part a,b,c,d
A particle with charge of 2 (HC), mass of 2X10-20 (kg) and velocity of 200(m/s) enters into a magnetic field of 0.06 (T). The particle experiences a force of 1.01x10-S(N) in the magnetic field. A) Calculate the angle between velocity and magnetic field directions. B) Calculate the acceleration of charged particle in the magnetic field. C) Draw a diagram showing direction of velocity, magnetic field, force and the angle between velocity and magnetic field, using...
2. Particle 1, with a charge q. 4.0 C and a speed v1 700 m/s travels at right angles to a uniform magnetic field. The magnetic force it experiences is Sx10N. A Second particle, with a charge 92 50 uC and a speed v2 1300 m's travels at an angle of 55° relative to the same magnetic field. Find (a) the magnitude of the magnetic field, and (b) the magnitude of the magnetic force 1 exerted on particle 2.
The force on a charged particle moving in a magnetic field can be computed as the vector sum of the forces due to each separate component of the magnetic field. As an example, a particle with charge q is moving with speed v in the? y-direction. It is moving in a uniform magnetic field Part A What is the x-component of the force F? exerted on the particle by the magnetic field? Part B What is the y-component of the force...
The speed of particle with 9e C charge is 7.6x104 m/s, and the magnitude of the magnetic force is 15.4 x10-15 N. What is the magnitude of the magnetic field if the particle is traveling 16º to the field? (Recall e is the magnitude of the charge of an electron.)