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An article suggested that yield strength (ksi) for A36 grade steel is normally distributed with μ 45 and σ = 5.0. (a) What is the probability that yield strength is at most 39? Greater than 63? (Round your answers to four decimal places.) at most 39 greater than 63 (b) what yield strength value separates the strongest 75% from the others? (Round your answer to three decimal places.) ksi You may need to use the appropriate table in the Appendix of Tables to answer this question.

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aWhen x-39; x_μ 39-45 The probability that yield strength is atnost 39 is p rs 39 -p(zs-1.2) 1-0.8849,, by standard normal table 0.1151 When x - 63; 3.6 The probability that yield strength is greater than 63 is P(x> 63) Pz>3.6) 1-0.9998, by standard normal table 0.0002 (b)The z score corresponding to the lowest 25% ie:025 is -=-0.674 x-45 x = 45-(0674 )(5) x = 4 1 .630

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