Question

<Chapter 8 Homework Item 8 8 of 19 Part A Draw a Hess's law diagram depicting the energy changes for the following reaction: CH4(g) + 2Cl2(9)CH2Cl2(g) + 2HCI(g) CH (g) + Cl2 (9)+CH3Cl g) + HCl(9) AH = -98.3kJ CH,CI(9) + Cl2(9) CH, CI, (g) + HCI(9) AH = -104kJ Drag the appropriate labels to their respective targets. Reset Help AHⓇ = -104k.) AH* = -98.3kJ C HCl(g) + HCI+C12(g) AH° = –202kJ Products CH CI (9) + 2HCl(9) Reactants CH (9) + 2Cl (9) Submit Request Answer Provide Feedback Next >

Hi, I have problem solving this...

Answer 1

According to the Hess's law : For a chemical reaction , the net heat change (∆H ) will be same same weather the reaction occurs in one step or several steps .

Let a reaction when occurs in one step

A -----> C ∆H = ∆H₁

But when the same reaction occurs in two steps

A -------> B ∆H = ∆H₂

B ------> C ∆H = ∆H₃

Then according to the Hess's law

∆H₁ = ∆H₂ + ∆H₃

We have to find CH4(%) +2012 > CH, Cl (4) +21ccy) -- 1° from given data CH469) + ck (Y) = CH3 (J) +HULCI) OH'= -98.3kJ CH, C9) + (3)>CH,C1, 4)+H :14) Hºs do4kg. CH4 (8) +241249) → Chel()+ Helly) According to lesin low; <pHº=698.3-109)K fjl= -202:3k.

houbone Vierah CH404) +2Cl (9) | *H*=-98-3K) JOH° = -202 K3 CH, celu) + Hel+ELAH | 24°= -10 467) CH, Cl2 CY) + 2 Hely)