Question

Question Help Claim: The mean pulse rate (in beats per minute) of adult males is equal to 69 bpm. For a random sample of 138 adult males, the mean pulse rate is 68 5 bpm and the standard deviation is 115 bpm. Find the value of the test statistic The value of the test statistic is (Round to two decimal places as needed) Enter your answer in the answer box and then click Check Answer

Answer 1

Test of Significance related to a Uniform Normal Derhu n I let 2 d....son be an observed sample from Nr. o population - Define , a IIx and = I Į (xi-2) ay To test to: pon. 9. Hi ha mo. m 2 Case - Ilo known ll - let raso (known). Under Ho: M = 4o. & (5)= Mo, it is expected that (X-Mo) is small. But if (x-4) is auité large in magnitude, we shall suspect Ho aq Hi & give support to Hi Note that under Ho. A N (Mo, To/n) in (Xinho) ~N(0,1) the disth is ind To An (x-ho) is the lest statistic of Ho: Mano : of parameter. let & be the chosen level of significance. If observed in Cot-holloc where c, ů a chosen such that — we reject Ho in favoue of Hi- Pro [ 1 Fr (88-10) / sc] = x 2 Pro [ (in (7-10 Pito [ &n (X-Mo) y c] = al. . * c = Tx/2 as TWN(0,1). Ta/2 = upper &/ the point of (011)

Hence, if nac-uo) Tah we reject Ho: - to as. Hi: MT. at & level of significance. www.visionrxlab.com X- pulse rate (in beats per minute). XNN. (0,02). Ma popular r = 1 Standard Clam M - 69. : Chinelo HoMeMo , Haita deviation На: дио na Saunal size 138 Sample X = 10.05.2 mean a 68.5. sländando nos. 30 deviation T test statistic & X-M. & 6805-69. slun OC 1.5/5138 -0.51 Ans.