Question

For the problem do the following: Explain how to create the construction using a compass and straightedge only, draw the construction and prove it. Here is the question: 1.) describe how to construct a triangle ABC given the length a and the side length of the altitudes h B and h C at the vertices B and C respectively. ***Follow this example as a guide. Note that this picture is not for the question above and is simply an example! Start with angle BAC and construct a circle centered at A on JABI and let it intersect the ray AC at the point C'. Then, construct a circle centered at B on IBC'I and a circle centered at C' on |C'Bl intersecting at point D. Then AD bisects Angle BAC Proof: Notice that IBDI.1C'DI and IABI.IAC'I and IAD|sADI so triangle ABD is congruent to triangle AC'D by SSS. Therefore, angle BAD-Angle C'AD

Answer 1

By the Given figure, To prove PA = AB Join OA and OB consider OAP and OBP OP = common side OA = OB radii off the circle OPP = OBP = 90 degree Therefore Angle between radius & tangent Thus, we can say PA = PB corresponding parts of congruent triangles are congruent.