Question

D1 D2 1N4002 1N4002 V1 "v. 40Hz 0° D4 D3 1N4002 1N4002

Vs =10 pk VD=0.7 F=40Hz

Given this ciruit

the ripple voltage is calcuted using the following equations for CR>>T/2

vr with no capacitor = Vs -2*VD

Vr with capacitor = Vs-2VD / 2R*F*C

Load	VR theory	VR experiment
R no capacitor	8.6 V	8.8V
C=10uF	2.287 V	2.2 V
C=22uF	1.039 V	1.08 V
C=47uF	486.6 mV	394 mV

Give possible reasons for the variation between the theoretical and experimental results.

Hint: deals with ideal diode and CR>>T/2.

Answer 1

Reasons Possible for Variation between the theoretical and experimental results In theoretical we took RC > > T/2 but in experimental we take RC almostequalto T/2 For theoretical with Capacitor V_R = T(pi - theta/4 pi squareroot 3 RC The high dispersion inside the capacitor does not Justify very precise formulas In Practical diode the Diode voltage various from 0.6 V to 0.9 V The tolerance of capacitor compensates typical negative errors. Diode conduction angle 2 theta should be taken into account for experimental view. Practical resistors are considered in experiments hence the output is varied.