The standard cell potential (E°cell) of the reaction
below is -0.55 V. The value of Δ G° for the reaction is ________
J/mol.
I2 (s) + 2Br- (aq) → 2I- (aq) +
Br2 (l)
The standard cell potential (E°cell) of the reaction
below is -0.55 V. The value of G° for the reaction is
________ J/mol.
I2 (s) + 2Br- (aq) 2I-
(aq) + Br2 (l)
| 5.5 ⋅ 10-6 |
| 1.1 ⋅ 105 |
| 0.55 |
| 0.54 |
| none of the above |
2Br^-(aq) -----------------------> Br2(l) + 2e^- E0 = -1.09v
I2(s) +2e^- -------------------> 2I^- (aq) E0 = 0.54v
-----------------------------------------------------------------------------
I2 (s) + 2Br- (aq) ---------> 2I- (aq) + Br2 (l) E0 cell = -0.55v
E0 cell = -0.55v
G0
= -nE0 cell*F
= -2*-0.55*96500
= 106150J = 1.1*10^5 J >>>>answer
The standard cell potential (E°cell) of the reaction below is -0.55 V. The value of Δ...
The standard cell potential (E°cell) of the reaction below is -0.55 V. The value of Δ G° for the reaction is ________ J/mol. I2 (s) + 2Br- (aq) → 2I- (aq) + Br2 (l)
53-54
53) The standard cell potential (E®cell) of the reaction below is -0.55 V. The value of AGº for the reaction is J/mol. 12 (s) + 2Br- (aq) → 21- (aq) + Br2 (1) A) 0.55 B) 5.5 x 10-6 C) 1.1 x 105 D) 0.54 E) none of the above 54) The standard cell potential (Eºcell) of the reaction below is +1.34 V. The value of AGº for the reaction is kJ/mol 3 Cu (s) + 2 MnO4- (aq)...
The standard cell potential (Eºcell) of the reaction below is -0.55 V. The value of AGº for the reaction is _ J/mol. 12 (s) + 2Br (aq) → 21+ (aq) + Brz (1) Select one: O a. 0.54 O b. 0.55 c. 5.5 x 10-6 O O d. 1.1 x 105 o e. none of the above The structure of 2,3-dimethylheptane is CH; Select one: CHCHZ O a. CH2 - CH2 - CH2 - CH2 H3C CH3 b. CHÚCH-C-CH-CH3 CH3...
Sulfuric acid is a very strong acid that can act as an oxidizing agent at high concentrations (very low pH, or even negative pH values). Under standard conditions, sulfuric acid has a low reduction potential, SO42−(aq)+4H+(aq)+2e−⇌SO2(g)+2H2O(l), +0.20 V which means it cannot oxidize any of the halides F2, Cl2, Br2, or I2. If the H+ ion concentration is increased, however, the driving force for the sulfuric acid reduction is also increased according to Le Châtlier's principle. Sulfuric acid cannot oxidize the...
Calculate the equilibrium constant for each of the reactions at 25∘C. Standard Electrode Potentials at 25 ∘C Reduction Half-Reaction E∘(V) Fe3+(aq)+3e− →Fe(s) -0.036 Sn2+(aq)+2e− →Sn(s) -0.14 Ni2+(aq)+2e− →Ni(s) -0.23 O2(g)+2H2O(l)+4e− →4OH−(aq) 0.40 Br2(l)+2e− →2Br− 1.09 I2(s)+2e− →2I− 0.54 A) 2Fe3+(aq)+3Sn(s)→2Fe(s)+3Sn2+(aq) (answers are not 4.1x10^5, 3.3x10^3, 2.7x10^10, or 2.6x10^10) B) O2(g)+2H2O(l)+2Ni(s)→4OH−(aq)+2Ni2+(aq) C) Br2(l)+2I−(aq)→2Br−(aq)+I2(s) (answer is not 1.7x10^18)
The standard cell potential (E°) of a voltaic cell constructed using the cell reaction below is 0.76 V: Zn(s) + 2H+(aq) → Zn2+(aq) + H2(g) With PH2= 1.0 atm and [Zn2+] = 1.0 mol L-1, the cell potential is 0.37 V. The concentration of H+ in the cathode compartment is ________ mol L-1. Answers: 2.6 × 10-7 5.1 × 10-4 0.686.6 × 10-14 4.3 × 10-27
please helpppp!!!
7) The standard cell potential (E cell) f for the reaction below i ls -0 43 V. The cell potential for this at best cong (6 polnts) Ag Acid 6 natch the H idding 6e e cancel e, pposite pposite (e) e ancel is the he por Poten 8) The standard cell potential (E-cell) of the reaction below is .0.126 V. The value of ΔG" for the reaction is Pb (o) 2H (aq)Pb2+ (aq) H2 (g) vith (6...
nF 30. The standard cell potential (Ecell) of the reaction below is +0.126 V. The value of AG° for the reaction is kJ/mol. Pb2+ (aq)+ H2 (g) Pb (s)2H (aq) E) -50.8 D)+12.6 C)-12.6 B) +24.3 A) -24.3
Calculate the standard cell potential and determind deltaG for a cell that utilizes the following reaction: Cl2(g) + 2Br-(aq) -----> 2Cl-(aq) + Br2 (l)
1) Calculate the cell potential, E°cell, for the following electrochemical reaction. Cu(s) + I2(g) → Cu+2(aq) + 2I-1(aq) E = ? a.-0.87 V b.-0.19 V c.0.19 V d.0.87 V 2) Calculate the equilibrium constant (Keq) for the following reaction at 25 °C? (Faraday's Constant = 96,500 J / V · mol) & (R = 8.314 J / mol · K) 2Fe+3(aq) + Sn+2(aq) → 2Fe+2(aq) + Sn+4(aq) K = ? a. 4.04 x 107 b. 3.44 x 1018 c. 4.48...