Question

An object is placed in front of a convex mirror with radius of curvature = 19 cm. The object's height is 2.8 cm and it is initially 23 cm in front of the mirror. Find the (a) location and (b) height of the image. Next the object moves closer to the mirror, so the object distance is 3.1 cm. Again, find the (c) location and (d) height of the image. (e) What is the ratio of the image height when the object distance is 3.1 cm to that when the object distance is 23 cm? im S First object position Second object position NS | (a) Number 16.723 (b) Number 1.010 (e) Number 9 2.337 (d) Number 12.11 (e) Number 12.5 units.com units cm units.com Units cm units no units : Click if you would like to Show Work for this question: Open Show Work

Answer 1

(a)Locati on of the image can be calculated as follows Focal length of the convex mirror is R19 cm f -9,5 cm 2 1 1 1 1 9.5 cm 23 cm v -6.723cm 6.72 cm formulae find height of the image (b) Using magnefi catie - (-6.723 cm (2.8cm) 23cm =0.818 cm 0.82cm (c)Location of second image distance can be calculated as foll ows: 1 f 1 1 9.5 cm 3.1cm V-2.337 cm -2.34 cm (d)Using magneficati on formulae find height of the image (-2.337 cm) (2.8 cm) 3.1cm =2.11 cm (e)Now compare image heights in part-d & part-b 2.11cm 2.582,6 0.818 cm