Question

out of 1.00 Questions Newton's law for universal gravitation can be written as: F = mm where in the universal gravitational Constantin Nm .m, and are the masses in kg and is the distance between the centre of mass of mand me in m. The force on mass mis towards mass my. Let stand for the distance from the centre of mass of a planet with mass M. A satellite with mass mis moved along a straight line from x am tox=bm, where b>a. Part 1) Write an integral expression for the work done by the gravitational force on the satelite as it moves from x ato x = b. W =-C**(x)dx) Your lost a wer was interpreted as follows The variables found in your answer were al Your s w er was interpreted as follows The variables found in your answer were: where is a constant greater than one and fix) > 0 only depends on and no other variables Part 2) Solve this integral to give an expression for the amount of work done by the gravitational force WE Part 3) the satelita is released from rest at what speed will it have when it returns to the point a? STACK, use the port function. For example, to type VSE + 2 you would type 5x+2). Note Recall that to enter a square root in Check

Answer 1

Prom Nasfonh lo of Goa taio, he Gt artationa d beliscen tlonet omd lhc .3atelt te 1 = "" der atraeron Work den bn the satellite to di flaing it du e Foeer diea GmM dw

aing / Gm Md 22 12 Givn M Compai Cenremt C= X. 1a, Pantz: 1:44 () GMM (9-5) 1 x ab GmM (A-1) at

Parfs: hi ufeetire ma of the fatces The ON GmN GmM 1 (1) 2 G(m tM) 4) ms