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A 66-kg skier starts from rest at the top of a 1200-m-long trail which drops a...

A 66-kg skier starts from rest at the top of a 1200-m-long trail which drops a total of 180 m from top to bottom. At the bottom, the skier is moving 11 m/s.How much energy was dissipated by friction?

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Answer #1

given

m = 66 kg ,

h = 180 m ,

v = 11 m/sec ,

total length = 1200 m

now using \Delta E = 0

then using equation

m g h - Efriction - 1/2 m v2 = 0

66 X 9.8 X 180 - Efriction - 0.5 X 66 X 112 = 0

- Efriction = 3993 - 116424

Efriction = 112431 J

the energy was dissipated by friction is Efriction = 112431 J

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