Question

PLEASE SHOW ALL LOGICAL STEPS TO SOLUTION FOR PROPER CREDIT! 1.An electron having an energy of 6 eV is incident on a potentiial barrier of thickness 0.15 nm and height 10ev a) Find the probability of transmission through the barrier. b) If a current of 8x10 such electrons per second are incident on the barrier, how many will get through each second? How many reflected back? c) What is the transmission current in Amperes( Coul/sec)? 10 ev 6ev

Answer 1

(9) Transmission constant is given by T: 1668.) 1 S exp(-250) tij where Kat 206+ E) W 2 we have vor loer E = GeV = K = - 249,11310-314X16X10-19 d (1005x10-34 ja = 105.76667 1018 1.02 84x1019 may a = 0.15 am Ky = and we are given oqci) = T=14 (4) 1976) exp (- 2x10mg T= 1685 * fx exp(-3,0852) = 3.84 exp(-3.0852) IT = 0.175571-Tramission . probability

(b) total no. of er = BX106 CN) no. of transmitted e-; Ne=ĄxN Pr + tramsminnion probability => Nq = 0.17557% 88106 NA = 1.40456x1067 and reflected er = N-No (8-1140456 Sitio e Ne = 6.595441067 Nexe (C) Tranminnion Current = amint we have tal sec . It = Nre = 1,40456460681.6X10119 = 2,24771

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