Question

QUESTION: What is the null value and alternative value for steps 6 and 7?

Step 6: Perform hypothesis test for population proportion

It is claimed that 67% of the months have highest monthly maximum temperatures above 19 degrees celsius (EMXT>190). Is there sufficient evidence to suggest that the proportion is 67%? Test this claim using a hypothesis test at 5% level of significance. In order to perform this function, you need to make the appropriate modifications to the provided script. In other words, you should:

Comment lines 94 - 100
Comment lines 106 - 113
Uncomment lines 119 - 125
Replace ???DATASET_NAME??? with manchesterweather
Replace '???VARIABLE_NAME???' with the variable 'EMXT'
Replace ???Xvalue??? with the appropriate value
Replace ???NULL_VALUE??? with the appropriate value for the null hypothesis
Replace '???TEST_TYPE???' with the appropriate alternative hypothesis

Step 7: Perform hypothesis test for population mean

It is claimed that average highest monthly maximum precipitation is 28 millimeters (EMXP=280). Test this claim using a hypothesis test at 1% level of significance. In order to perform this function, you need to make the appropriate modifications to the provided script. In other words, you should:

Uncomment lines 131 - 139
Replace ???DATASET_NAME??? with manchesterweather
Replace '???VARIABLE_NAME???' with the variable 'EMXP'
Replace ???NULL_VALUE??? with the appropriate value for the null hypothesis
Replace '???TEST_TYPE???' with the appropriate alternative hypothesis

##Step 6: Perform hypothesis test for population proportion
##-----------------------------------------------------------------------------
print ('Hypothesis Test - Step 6')
n = manchesterweather[['EMXT']].count()
x = (manchesterweather[['EMXT']] > 190).values.sum()
null_value = 67
alternative = '190'
print (prop_1samp_ttest(x, n, null_value, alternative))
print ('')

##Step 7: Perform hypothesis test for population mean
##-----------------------------------------------------------------------------
print ('Hypothesis Test - Step 7')
n = manchesterweather[['EMXP']].count()
df = n - 1
mean = manchesterweather[['EMXP']].mean()
std_dev = manchesterweather[['EMXP']].std()
null_value = 5
alternative = '280'
print (means_1samp_ttest(mean, std_dev, n, null_value, alternative))
print ('')

Answer 1

For Step#6, the null and alternative hypothesis are,

H0: p = 0.67

H1: p $\ne$ 0.67

So, the null and alternative value are,

null_value = 0.67
alternative = 'not equal to'

For Step#7, the null and alternative hypothesis are,

H0: $\mu$ = 280

H1: $\mu$$\ne$ 280

So, the null and alternative value are,

null_value = 28
alternative = 'not equal to'