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<Homework 4 Problem 21.74 ® 2019 » m Review Constants Periodic Table rail A proton follows the path shown in (Figure 1). Its initial speed is vo = 2.5x10 m/s. What is the proton's speed as it passes through point P? Express your answer to two significant figures and include the appropriate units. Figure 1 of 1 > "I HÅR xa X i . O 2 ? x.10" @ @ Up = vp = 2.2 • 166 4.0 mm The value should be entered as a single number or in scientific notation. No credit lost. Try again. -10 nC Submit Previous Answers Request Answer 3.0 mm Provide Feedback Next >

Answer 1

Page ① Answer: - proton's initial kinetic energy is K = 1 m vor = 1 / 2 x 1.678 10 -27 X (2.5X108) 4X167X10-27 X 6.25 81012 NA 5 x 1.04375X10-14 = 5.218 10-15 J potential energy at the start point is The P = kqa & 9x109 X 1.6 8 10 19 X (-10x10 9) 0.003 - 1.44X10-17 0.003 the -4.88 10 15 5 potential energy at the end point is P2 = KqQ r 6x10 CS Scanned with = 9x109x1,6x10-19 X (-10X10-9) 0.oou

page @ = - 1.44X10-17 0.004 I - 3.6810-15 J Since energy is conserved: Kit P, = Katla 0 K2= Ki+P, P2 = 5.21x10-15 + (-4.8810-15) -(-3-6x10-15) = 5.21810-15 _ 4.8x10-15 +3.6x10-15 = 4.01810-15 J I mur= 4.01810-15 vr = 4.01810-15X2 v² = 4.01x10-15 x2 1.67X1o-2 v = 8.02X 10-15 1.67X10-27 V - 4802395209580 N= √4802395209580 V= 2191436.7961441 V= 2.198106 mis The proton speed as it passes through point pis 2:19X10*m/s CS