Question

Chen 1113

4 b. 0.070 00 m = c. 53.50 g = 4 Convert 0.000 092 67 to scientific notation (without rounding). 9.267x10-5 If a 3.50% (w/v) citric acid solution contains 3.50 grams of citric acid in every 100.0 mL of the solution, how many grams of citric acid are present in 250 mL of the 3.50% (w/v) solution? Show your work using dimensional analysis and report your answer with the correct number of significant figures. What volume of the 3.50% (w/v) citric acid solution described above would be needed to provide 628 mg of citric acid for a reaction? Show your work using dimensional analysis and report your answer with the correct number of significant figures. (You should know the relationship between grams and milligrams.)

Answer 1

Convert 0.00009267 = 9.267 * 10^(-5)

Question 1:

3.50%(m/v) represents 3.50 grams of citric acid is present in 100.0 ml of solution.

Grams of citric acid present in 250.0 ml of solution = 3.50/100.0 * 250.0 = 8.75 grams

Hence the answer in 3 significant digits will be 8.75 grams

Question 2:

Mass of Citric acid needed = 628 mg = 0.628 g

Let the volume required be V(ml)

0.628 = 3.50/100 * V

V = 62.8/3.50 = 17.94 ml

Hence the answer in three significant digits will be 17.9 ml

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