A particle starts from 8.0 m at t_0 = 0 and moves with the velocity graph...

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A particle starts from 8.0 m at t_0 = 0 and moves

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Answer 1

Answer #1

Part B: Informatio of part A is necessary.

Part C:
From the graph the acceleration is:

$a = \frac{\Delta v}{\Delta t}= 4/1 = 4 m/s^2$

the position of the object is:

$x =x_0+v_0t +\frac{1}{2}t^2$

$x = 8.0-4.0t +2.0t^2$

for each time:

$x_2 = 8 m$

$x_3 = 14 m$

$x_4 = 24 m$

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Answer 2

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