Question

he Flying Physics Brothers, Stu and Lou, end their act by both being shot out of cannons. They fly through the air and land at the same height they left the cannons. Assume air resistance can be neglected.

Stu's initial speed is 14.63 m/s and Lou's initial speed is 23.90 m/s. Stu leaves the cannon at an angle of 60.6^o and Lou leaves the cannon at an angle of 28.1^o. As usual, the angles are measured upwards from the positive-x (horizontal) direction.

What is the difference between the time Stu is in the air and Lou is in the air? In other words, calculate:

Δt=tStu, f−tLou, f.

IStu, f TLou,

Your answer should be in seconds to at least three significant digits to avoid being counted incorrect due to rounding. Obviously, your answer may be positive or negative depending on who is in the air longer.

Answer 1

2x 14-63xSi (60.6) 9.81 stu 2x 23.goxs,'y (28.リ Atu니 齊 円,81 A4Lou : 2.25s sec At O. 303s Sec