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Given a chemical reaction below, 2502(g) + O2(g) = 2 503(8) Kc = 2.7 102 at 960K what is the value of K, for this reaction? (
Question 9 1 pts The reaction system SO2(g) + NO2(g) = NO(g) + SO3(g) is at equilibrium. When NO2 is added to the container,
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Answer #1

1) 250g & O2 t 250₃ Kp=ke. (RT) Oh [on= moles of gos product side -moles of gos sactant side) & (2- (211)) = -1 Kp = 2.7X10²

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