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If the voltage measured across 2.2 kΩ resistor is equal to 6V, what is the magnitude of the current that flows through this r
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Answer #1

Voltage = 6 V

V= I*R

Voltage= Current* Resistance

R= 2.2 kohm

I=V/R

I=6V/2.2 kohm

I= 2.727 mA

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