P(|z| < Zc)=0.95
=p(-zc < z < zc) =0.95
p(-1.96< Z < 1.96) =0.95
3. Let Z be a continuous random variable with Z-N(0,1). (a) Find the value of P(Z <-0.47). (b) Find the value of P(Z < 2.00). Note denotes the absolute value function. (c) Find b such that P(Z > b) = 0.9382. (d) Find the 27th percentile. (e) Find the value of the critical value 20.05-
Need the answers diagramed
6) Find the indicated probabilities. [3pts. each] a) P(z < 1.28) b) P(-2.15 z 1.55) c) P(z> 1.64) d) ? = 5.5, ? = .08, P(5.36 < x < 5.64) e) ?--8.2, ?-7.84, P(x-5.00) 18.5, ? 9.25, P(x < 5.24) tion 3nts
1. Find the value of * that yields the probability shown a. P(Z <**)-0.0075 b. P(Z <=*) -0.9850 C. P(Z >z*) - 0.8907 d. P(Z >»*) -0.0110 For #1: a) P(Z < z*) = 0.0075 b) P(Z <z*) = 0.9850 c) P(Z > z*) = 0.8997 d) P(Z > z*) = 0.0110
3. Find the value of z such that the following are satisfied: a. P(Z < z) = 0.85 b. P(Z <= z) = 0.5 C. P(Z > z) = 0.85 d. P(-1.24 < Z < z) = 0.85
just number 8
6. 20 = Find zo if (a) Find zb if (b) Find zc if (c) P(-20 < < < zo) = 0.3400 P(Z < zb) = 0.3015 P(Z > ze) = 0.7995 zb = 7. Find x if P(X< x) = 0.6179 X is the normal r.v. N(10,2). x = .. 8. Find y if P(Y<y) = 0.9729, Y is normal r. vN (0,4) y = ........ (a) Find P(x > 110) ifr.v. X = N(100, 102)....
EXERCISES the mgf of the random variable X, find P(x < 5.23). d so that P(e < X < d) = 0.95 3.3.1. If (1-2t)-6, t<½, is V3. .3.2. If X is χ2 (5), determine the constants c and and P(X < c) = 0.025.
Which of the following defines an inner product on R^3 <(x,y,z),(a,b,c)>= xa+2xb+3xc <(x,y,z),(a,b,c)>= xy+za+bc <(x,y,z),(a,b,c)>= xa-yb+zC <(x,y,z),(a,b,c)>= (x+z)(a+c)+(2x+2y)(2a+2b)+(3x+z)(3a+c)
3. Fin a) P(z < 2.37) b) P(z > -1.18) c) P(-1.18 < z < 2.37)
For a standard normal distribution, find: P(Z < c) = 0.2523 Find c.
For a standard normal distribution, find: P(0.61 < z < 2.92)