1) The moles of HEPES and KOH used are calculated:
n HEPES = M * V = 1.5 M * 0.0125 L = 0.01875 mol
n KOH = 3 M * 0.00619 L = 0.001857 mol
The KOH reacts with the HEPES and forms HEPES-KOH, the pH is calculated:
pH = pKa + log (n HEPES-KOH / n HEPES) = 7.48 + log (0.001857 / 0.01875 - 0.001857) = 6.52
a) If it is an acceptable buffer, since the pH obtained is within the range of +/- 1 pKa.
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