Question

VISION BACK NEXT Chapter 12, Problem 039 For the stepladder shown in the figure, sides AC and CE are each 3.01 m long and hinged at Bar AD is a tie-rod 0,832 m long, halfway up. A man weighing 787 Ndimbs 2.26 m along the ladder, Assuming that the floor is frictionless and neglecting the mass of the ladder find (a) the tension in the tie-rod and the magnitudes of the forces on the ladder from the floor at (b) A and (c) E. (Hint: Isolate parts of the ladder in applying the equilibrium conditions.) audy. Units Units (a) Number (b) Number (c) Number Units - Show Work for this question: On Show.Wok

Answer 1

The force equation is, F =W-F, F, = Fg I-F, =0 wL cos® – F_1 cos8 w(L –d)cose-r sin o =0 FI cos6–7 ()sin o=0 2cos = tane I wd I - I tan = 1.56144 m =1.56 m tano=1.56144 0.832 2 T = 3.75 (787) (226) 3.01(3.75) =157.57 N (b) F = W-F, = (1-1 = 491.548 N =491.55 N

Simlarly 2(3.10) = 286.87 N