Question

What is the date and standard time in Paris, longitude 01 15'15"E of Greenwich, when it is in Ottawa, longitude 73°53'30"W of Greenwich, 23h45m of April 30, 2006?

Answer 1

To simplify 360⁰ has a time difference of 24 X 60 min. So 1 degree will have a time difference of 24X60 /360= 4 min.

Now when we move towards west to east the time will be added

So total distance from west to east = 73⁰53'30'' + 01⁰15'15'' = 75⁰8''45'

Now,

75⁰ = 75X4 = 300 minutes

8' = 8 X 4 = 24 seconds

45' = 3 second

Total 5^h0^m27^s

So Paris is 5 hours and 27 seconds ahead of Ottawa

Time of Paris is 23^h45^m + 5^h27^s - 24^h = 4^h45^m27^s

And date will also change that is

1 may 2006

So the time in Paris is 4^h45^m27^s and date 1^st of May 2006