Question

Compute the Thevenin equivalent of the circuit shown below. Note that the Thevenin voltage and the Thevenin resistance may be dependent on k. S 112 122 122 12 -Тоа (Aiv ki ob

Answer 1

Answer in ir theven in voltage (8th) - - - .-? Ve=wet w in to van move a toc Utha =ve Toa [thvel v Applying KEL at Node ② Vaa Ve + Vorl=ki + Vd 1 = ki 11 2V4 - With = titi

At Node © ve-l + ve-lo ao Ish-lt Vithald so 12 Vith-Nd = 1 0 From figure (Walk) Wring ohnis Law is l_Ve 1 = lydh ti = 1 - Ven 2 wsing equation of 28d - Vm= KC1- Vh)+1 2Vd - With =k-kithti 2 Vd a Vth tk Vth = kal 12 Vd + x =19 with = K+

using equation ® 4 2 (Q Vth-1) + K-1) Vith =k ti 4 Vith -2 + k Vrh - Vth - Kel (k +3) Vth = K+ 3 - t3 → Yth = Vth = lv. | And Kt3 othevenin Resistance (Rita) Ve=W et au Lama 4 VOLIA Vabe Ruth Applying KEL at Node a + vente = 2 Ve-Vd as A at Node ② Vor- YC + Voght ki > Vo - Vo = Ki+1 46

using oohms Law (V=FR) * TV > = 1-Ve ☺ using equation ® 4 @ 2 V8 - Ve = kli-Ve). 4) 2. Vd - VetkVc = kt! 12 Vd +(K-1) Ve zktit ☺ ausing equation @ 40 2 (2 Ve-2) +(K-1) Ve = K+ Avec A + RVC - Ve = x+1 (+3) Ve = K +5 Te = (k+5) TK+3) Frrom equation © î = 1- (K+5) = 1 = (x+3 - *-5)/K+3 (Kat 3)

(k+3 A Now moving a to b as shown in figure 6 Vab - 149 + 1X1 -1 = 0 vab = 2-1 * Vab = 2K+6 +2 Kt3 Vab = 2 + 2 K43 Vab = (2k + %) v (K +3) now using shimiz Lave (Vair) Rona Vab - (2K+8) n. that I was (K+3) Ron = 223 With=lv obo Note Hoove method to find the Rth oniginal Network is having can be applied when the at least one independent source.