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Let E = { x is in [0,1) : x has a decimal expansion involving 1's,...

Let E = { x is in [0,1) : x has a decimal expansion involving 1's, 2's, and 3's only}. Show that |E| = |R|.
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#E- is in 0,0: x has a decimal expansion involving 16, 298, and 3 buly}. Clearly. Op E ic uncountable. Ket, it possible , [0assumed enumeration fr. xs, uz , ..., nr. ... } of 100 E So the assumption that is countable - leads to a contradiction. . .I hope you understand my work. If you still have any doubt please let me know in comments. I shall reply you as soon as possible.

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