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Need help with chemistry please.
5. A 12.5 gram walnut is burned under 100 ml of water. How many calories did the water absorb if its temperature went from 22.5 c to 95.5 C? Answer
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Tem P. differenCL (Ar)= (95-5-22-5)c sweased dusing 3819. 그9.5-T g= 3.81 kT

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