Question

JLULU) LELIUI 22/12/userdhelds14&effectiveUser=dfields14&key=UVNVOgb8! Lecture22: Problem 12 Previous Problem List Next (1 point) You have only two chances at this problem. To test the hypotheses Hoy > 192.33, H.: < 192.33 for a normal population at the a = 0.05 significance level, a sample of size 14 was drawn and found to have mean T = 184.55 and standard deviation s=22.00. Which of the following is closest to the p-value that was found? (Assume that the p-value was found correctly.) OA.0.10 OB. 0.12 OC. 0.11 OD. 0.09 OE. 0.08 Which of the following is the correct conclusion from the test?

Answer 1

$\mu_0 = 192.33$
n = 14
$\\s = 22 \\\bar{X} = 184.55 \\\alpha = 0.05$
The test hypothesis is
$\\Null\;Hypothesis --> H_0: \mu \ge \mu_0 \\Alternate\;Hypothesis --> H_1: \mu < \mu_0$
Now, the value of test static can be found out by following formula:

Χ– μο - s/n . 184.55 – 192.33 22.0/14 to = -1.3232 to =

Using Excel's function =T.DIST(t0,n-1,TRUE), the P-value for t0 = -1.3232 in an power-tailed t-test with 13 degrees of freedom can be computed as .
Since P = 0.1043 > 0.05, we fail to reject the null hypothesis $H_0: \mu = 192.33\ at\ \alpha = 0.05$
Option A 0.10 is correct
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