please help finish chart and answer questions.
Homework Answers
| 4Fe | 3O2 | 2Fe2O3 | |
| Initial | 16 | 15 | 0 |
| Change | -4a= -16 | -3a = -12 | +2a=+8 |
| End | 16-4a = 16-16 =0 | 15-3a=15-12=3 | +2a=8 |
a=4 ,as Fe is limiting reagent, all the available Fe will get consumed.(explanation given in answer to the first question)
Therefore, -4a=-16
a= 4
1. From the balanced chemical equation,we see that 4 moles Fe of requires 3 moles of O2 to react completely.
Therefore, 16 moles of Fe would require = (3/4)x16 moles of O2 = 12 moles of O2
Available moles of O2 are more than that required to completely react with available Fe.
Thus, we can say that amount Fe is lesser than that required to completely react with O2. Therefore, Fe is the limiting reagent.
2. Theoretical yield is calculated based on the amount of limiting reagent.
Fe is the limiting reagent.
From the balanced chemical equation , we know that 4 moles of Fe produces 2 moles of Fe2O3..
Therefore 16 moles of Fe will produce= (2/4)x 16 moles of Fe2O3.
= 8 moles of Fe2O3.
Theoretical yield of Fe2O3 == 8 moles
3. O2 is the excess reactant. Explanation is done in anwer to question no.1.
4. Percent yield=( Actual yield/ Theoretical yield)x100 %
=(2 moles/8 moles )x100%
= 25%
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so based off of the answers in the chart, I need help
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can anyone help me finish using the numbers already filled
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