Question

What is the molecular equation and the net ionic equation for the following reactions:

Sodium iodide + iron (III) chloride

Sodium iodide + tin (IV) chloride

Answer 1

Molecular equation representing the reaction between the aqueous solutions ofiron (III) chloride and sodium iodide is as follows: FeCl, (a)+3 Nal (aqel (s) +3 NaCl(aq) Solution Ionic equation for the above reaction as follows Fe* (aq) + 3C1-(aq) +3Ņa+(aq) + 31-(aq) → Fel3(s) +3 Na+(aq) + 3C1-(aq) Cancel the ions that are common on both sides of the equation to get the net ionic equation, these ions are known as the spectator ions. In the above reaction, Na and CI ions are the spectator ons le (a): 3Cl (w) .:. 3Na (w) .1.31 (m) s lil ( )+3N (w).:. 3Cİ (w) Therefore, the net ionic equation is Fe()+31(a)Fel (s)

Molecular equation representing the reaction between the aqueous solutions oftin (IV) chloride and sodium iodide is as follows SnCl4 (aq) + 4 Nal (aq)-> Snl4 (s) + 4 NaCl (aq) Ionic equation for the above reaction as follows: sn'. (aq) +4 Cl-(aq) + 4 Na+ (aq) + 4 1-(aq)--Sn14 (s) +4 Na"(aq) + 4 Cl-(aq) Cancel the ions that are common on both sides of the equation to get the net ionic equation, these ions are known as the spectator ions. In the above reaction, Na and C ions are the spectator ons Therefore, the net ionic equation is Sn (aa) +4I (aa) SnI,(s)